On-line Math 21

On-line Math 21

4.5  Curve Sketching

Example 5 f(x) = x4+4x3+4x2-2 .

Solution


   Intercepts

Not every calculation can be equally easy for these functions. Typically, the problems you see in the texts have perhaps one, or two, of: intercepts, or critical points, or inflection points, easy to find. The others are usually difficult to evaluate. That is especially true with this problem. I do not want to find some 4-degree formula, like the quadratice formula, to solve it. Such a formula does exist, but you don't want to see it.

The only intercept we can easily find is the y -intercept at (0,-2) . I used Maple tro draw a graph, and saw that there are x -intercepts at about 1/2 and -5/2 (they are not exactly at those points, but close).


   Increasing/decreasing, and critical points

f¢(x) = 4x3+12x2+8x , so critical points occur when
0
=
f¢(x)
=
4x3+12x2+8x
=
4x(x2+3x+2)
=
4x(x+1)(x+2),
so the only places where f¢(x) = 0 are x = 0,-1,-2 . The values are: f(0) = -2 ,
f(-1)
=
(-1)4+4(-1)3+4(-1)2-2
=
1-4+4-2
=
-1,
and
f(-2)
=
(-2)4+4(-2)3+4(-2)2-2
=
16-32+16-2
=
-2,
or the critical points and values are (0,-2), (-1,-1) , and (-2,-2) .

In between, the sign of f¢(x) is given as follows:


   Concavity, and inflection points

f¢¢(x) = 12x2+24x+8 , so inflection points occur at solutions to
0
=
f¢¢(x)
=
12x2+24x+8
=
4(3x2+6x+2),
which has roots at
x = -1± 1
Ö3
,
using again the quadratic formula, or, really, Maple. Finding the y -values of these points is a hassle, let's not.

Here is the number line indicating the sign of the second derivative:


   Draw the graph

Use this information to draw a fair representation of the graph.

[Each of these items should trigger the appearance of a new drawing with that information added.]

Copyright (c) 2000 by David L. Johnson.


File translated from TEX by TTH, version 2.61.
On 21 Dec 2000, 00:34.