Subject: Ravenel's question From: Tom Goodwillie Date: Thu, 7 Jul 2005 13:09:43 -0400 To: Don Davis I have just one thing to add: This is mostly about the limiting case as n goes to infinity, which is clearly not what Doug was looking at, but I thought I would mention it because it's a clean simple statement. Of course, geometrically Z[x_1,...,x_m] can be thought of as the ring of functions on affine m-space A^m, and Doug's ring R, the ring of Sigma_n-invariants in the nth tensor power of that ring, is then the ring of functions on the nth symmetric power SP^n(A^m). Any function f on X=A^m determines functions on SP^n(X), for example the elementary symmetric polynomials e_j(f). These vanish for j>n. It is a well-known fact that in the case when m=1 the ring of symmetric functions has the elements {e_j(x_1), j=1 to n} as a polynomial basis. The case of m>1 is a lot more complicated, but here is one nice fact: in the (inverse) limit as n-->infinity, the ring is again a polynomial ring with a basis that is easy to specify. Doug was in effect trying to generate the ring of symmetric functions in the case of general m by considering e_j(f) where f is a generic linear function c_1x_1+...+c_mx_m. His elements are the coefficients of e_j(f) with respect to the various monomials in the "dummy" variables c_i. If those elements did generate the ring, then in particular the elements e_j(f) where f is a linear polynomial in (x_1,...,x_m) (with integer coefficients) would generate, which I guess they don't. However, the elements e_j(f) where f(x_1,...,x_m) is an arbitrary polynomial do generate. And using formulae like e_2(f+g)=e_2(f)+e_1(f)e_1(g)-e_1(fg)+e_2(g) one can reduce to the case when f(x_1,...,x_m) is a monomial. And using formulae like e_2(f2)=e_1(f)2-2e_2(f) one can reduce to the case when the monomial is not a power of another monomial. These are independent generators; that is, if j ranges over all positive integers and d=(d_1,...,d_m) ranges over all ordered m-tuples of nonnegative integers having no common prime factor, and x^d is shorthand for x_1^{d_1}...x_m^{d_m}, then the elements e_j(x^d) generate the ring of invariant functions, and in the limit as n becomes infinite they satisfy no relations. - Tom Goodwillie