Date: Thu, 18 Jan 2001 21:16:54 -0600 From: Bill Richter Subject: Re: response on embeddings by Hirsch, N immerses in R^(n+1), and by Whitney, N embeds in R^2n (on this point, I am confused by Mark Mahowald's comment). Frank, I think Mark's right, and it might be explained in his paper On obstruction theory in orientable fiber bundles. Trans. Amer. Math. Soc. 110 1964 315--349 or maybe his paper with Paul Goerss Immersions not regularly homotopic to embeddings. Amer. J. Math. 109 (1987), no. 6, 1171--1195. Trying to extend your `record in mathematical non-communication between colleagues', I haven't looked at these paper recently. Maybe John Klein will :) Mark's certainly extended Whitney's embedding work, and he may be blurring the exact line between Whitney and himself. We can certainly say this: The top cell of your stably parallelizable manifold N of dimension n falls off, so there's a stable degree 1 map S^n ---> N, which by Freudenthal we can obtain unstably (not uniquely) in pi_{2n-1} Sigma^{n-1} N So N Poincare embeds in R^2n-1 by Bruce Williams's metastable Poincare embedding theorem, since we're in a pi-pi situation. (In my homotopy theoretic proof in Duke J, the pi_1 don't cause any problems, nor does it in Bruce's proof.) Now Levine's proved a metastable smooth embedding theorem, but only in the 1-connected case, where we already know there's an embedding, by the Stallings embedding theorem, but even in the 1-connected case there are surgery issues that you must understandd much better than I. ________________________________________ From: William Browder Subject: Re: response on embeddings Date: Fri, 19 Jan 2001 8:55:42 MET Since I proved that the Kervaire invariant of such a manifold is 0 except possibly when n = 2^n - 2, that reduces the popssible exceptions. Bill > Date: Thu, 18 Jan 2001 15:14:12 -0500 > From: Frank Connolly > Subject: Re: embedding question > > Concerning Bill Dwyer's question: > The results of DeSapio (Annals, 1965) prove that a stably > parallelizable manifold N of dimension n (with n at least 5) embeds in > euclidean space of dimension 2n-1. There is one possible exception--when n > is congruent to 6 mod 8 and the Kervaire Invariant of N remains non-zero no > matter what framing is chosen. > (I suspect even this possible exception can be dispatched by some > geometrical expedient). > Moreover if N is k-connected, DeSapio shows the euclidean space's > dimension can be improved to 2n-2k-1, with the same exception, but also k > must be smaller than [n/4]. > Of course, by Hirsch, N immerses in R^(n+1), and by Whitney, N > embeds in R^2n (on this point, I am confused by Mark Mahowald's comment). > > Actually this question from Bill (eventually getting to me), and my > response technique, must represent some kind of a record in mathematical > non-communication between colleagues: not only is Bill's office a few steps > from mine, but also we just finished arranging to eat dinner together > tonight! > > Frank Connolly > > > >